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75 changes: 39 additions & 36 deletions numpy_questions.py
Original file line number Diff line number Diff line change
@@ -1,4 +1,5 @@
"""Assignment - using numpy and making a PR.
"""
Assignment - using numpy and making a PR.

The goals of this assignment are:
* Use numpy in practice with two easy exercises.
Expand All @@ -19,49 +20,51 @@


def max_index(X):
"""Return the index of the maximum in a numpy array.

Parameters
----------
X : ndarray of shape (n_samples, n_features)
The input array.

Returns
-------
(i, j) : tuple(int)
The row and columnd index of the maximum.

Raises
------
ValueError
If the input is not a numpy array or
if the shape is not 2D.
"""
i = 0
j = 0
Return the indices (i, j) of the maximum value in a 2D matrix.

Parameters:
X (np.ndarray): A 2D numpy array.

# TODO
Returns:
tuple: Indices (i, j) of the maximum value in the array.

Raises:
ValueError: If X is not a numpy array or not a 2D array.
"""
if not isinstance(X, np.ndarray):
raise ValueError("X must be a numpy array.")
if X.ndim != 2:
raise ValueError("X must be a 2D array.")

# Find the flattened index of the maximum value
flat_index = np.argmax(X)
# Convert to 2D indices
i, j = divmod(flat_index, X.shape[1])
return i, j


def wallis_product(n_terms):
"""Implement the Wallis product to compute an approximation of pi.
"""
Approximate the value of pi using the Wallis product.

See:
https://en.wikipedia.org/wiki/Wallis_product
Parameters:
n_terms (int): The number of terms in the Wallis product.

Parameters
----------
n_terms : int
Number of steps in the Wallis product. Note that `n_terms=0` will
consider the product to be `1`.
Returns:
float: Approximation of pi.

Returns
-------
pi : float
The approximation of order `n_terms` of pi using the Wallis product.
Raises:
ValueError: If n_terms is negative.
"""
# XXX : The n_terms is an int that corresponds to the number of
# terms in the product. For example 10000.
return 0.
if not isinstance(n_terms, int) or n_terms < 0:
raise ValueError("n_terms must be a non-negative integer.")

product = 1.0
if n_terms == 0:
return 2.0

for i in range(1, n_terms + 1):
product *= (4 * i**2) / (4 * i**2 - 1)

return 2 * product
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