|
4 | 4 | {
|
5 | 5 | "question": "1. Given T = 300 K, m<sub>n</sub> = 1.08 × 10<sup>-31</sup> kg, m<sub>p</sub> = 0.56 × 10<sup>-31</sup> kg, h = 6.626 × 10<sup>-34</sup> J·s, E<sub>F</sub> = 0.4 eV, E<sub>C</sub> = 0.2 eV, and E<sub>V</sub> = 0.1 eV, what are the electron concentration n0 and hole concentration p0?",
|
6 | 6 | "answers": {
|
7 |
| - "a": "n0 = 7.3 x 10<sup>26</sup> m, p0 = 1.1<sup>-3</sup> x 10<sup>18</sup> m<sup>-3</sup>", |
8 |
| - "b": "n0 = 2.5 x 10<sup>26</sup> m, p0 = 3.0<sup>-3</sup> x 10<sup>18</sup> m<sup>-3</sup>", |
9 |
| - "c": "n0 = 4.1 x 10<sup>26</sup> m, p0 = 1.8<sup>-3</sup> x 10<sup>18</sup> m<sup>-3</sup>", |
10 |
| - "d": "n0 = 5.2 x 10<sup>26</sup> m, p0 = 2.7<sup>-3</sup> x 10<sup>18</sup> m<sup>-3</sup>" |
| 7 | + "a": "n0 = 7.3 x 10<sup>25</sup> m<sup>-3</sup>, p0 = 1.1<sup>-3</sup> x 10<sup>17</sup> m<sup>-3</sup>", |
| 8 | + "b": "n0 = 2.5 x 10<sup>25</sup> m<sup>-3</sup>, p0 = 3.0<sup>-3</sup> x 10<sup>17</sup> m<sup>-3</sup>", |
| 9 | + "c": "n0 = 4.1 x 10<sup>25</sup> m<sup>-3</sup>, p0 = 1.8<sup>-3</sup> x 10<sup>17</sup> m<sup>-3</sup>", |
| 10 | + "d": "n0 = 5.2 x 10<sup>25</sup> m<sup>-3</sup>, p0 = 2.7<sup>-3</sup> x 10<sup>17</sup> m<sup>-3</sup>" |
11 | 11 | },
|
12 | 12 |
|
13 | 13 | "explanations": {
|
|
54 | 54 | "difficulty": "intermediate"
|
55 | 55 | },
|
56 | 56 | {
|
57 |
| - "question": "4. In an n-type semiconductor in the extrinsic region, given that ND = 5 × 10<sup>16</sup> , and ni = 9.65 × 10<sup>15</sup> m⁻³, what is the hole concentration p₀?", |
| 57 | + "question": "4. In an n-type semiconductor in the extrinsic region, given that NN<sub>D</sub> = 5 × 10<sup>16</sup> , and n<sub>i</sub> = 9.65 × 10<sup>15</sup> m⁻³, what is the hole concentration p₀?", |
58 | 58 | "answers": {
|
59 | 59 | "a": "1.72 × 10<sup>13</sup> m⁻³",
|
60 | 60 | "b": "1.86 × 10<sup>15</sup> m⁻³",
|
61 | 61 | "c": "2.09 × 10<sup>13</sup> m⁻³",
|
62 | 62 | "d": "1.95 × 10<sup>15</sup> m⁻³"
|
63 | 63 | },
|
64 | 64 | "explanations": {
|
65 |
| - "a": "Using the equations n₀ = N<sub>D</sub> and p₀ = n<sub>i</sub>² / n₀, we calculate p₀ as [calculated_value] m⁻³, which matches option [correct_option].", |
66 |
| - "b": "Using the equations n₀ = ND - NA and p₀ = ni² / n₀, we calculate p₀ as [calculated_value] m⁻³, which matches option [correct_option].", |
67 |
| - "c": "Using the equations n₀ = ND - NA and p₀ = ni² / n₀, we calculate p₀ as [calculated_value] m⁻³, which matches option [correct_option].", |
68 |
| - "d": "Using the equations n₀ = ND - NA and p₀ = ni² / n₀, we calculate p₀ as [calculated_value] m⁻³, which matches option [correct_option]." |
| 65 | + "a": "Using the equations n₀ = N<sub>D</sub> and p₀ = n<sub>i</sub>² / n₀, we calculate p₀ as 1.86 × 10<sup>15</sup> m⁻³, which matches option 'b'.", |
| 66 | + "b": "Using the equations n₀ = N<sub>D</sub> and p₀ = n<sub>i</sub>² / n₀, we calculate p₀ as 1.86 × 10<sup>15</sup> m⁻³, which matches option 'b'.", |
| 67 | + "c": "Using the equations n₀ = N<sub>D</sub> and p₀ = n<sub>i</sub>² / n₀, we calculate p₀ as 1.86 × 10<sup>15</sup> m⁻³, which matches option 'b'.", |
| 68 | + "d": "Using the equations n₀ = N<sub>D</sub> and p₀ = n<sub>i</sub>² / n₀, we calculate p₀ as 1.86 × 10<sup>15</sup> m⁻³, which matches option 'b'." |
69 | 69 | },
|
70 | 70 | "correctAnswer": "b",
|
71 | 71 | "difficulty": "beginner"
|
|
0 commit comments