find if value is sum of two ints in a array

others/arrays/set_col_rows_zero.py

@@ -0,0 +1,28 @@
+def set_cols_rows_to_zero(m):
+	len_rows = len(m)
+	len_cols = len(m[0])
+	list_pos = []
+
+	# finding zeros in the matrix
+	for i in range(len_rows):
+		for j in range(len_cols):
+			if m[i][j] == 0:
+				list_pos.append([i,j])
+
+	# replacing rows and cols by zeros
+	for pos in list_pos:
+		for j in range(len_cols): # add zeros on row
+			m[pos[0]][j] = 0
+		for i in range(len_rows):
+			m[i][pos[1]] = 0
+	return m
+
+test = [[1,2,3], [4,0,6], [1,3,8]]
+test2 =[
+		    [1, 5, 45, 0, 81],
+		    [6, 7, 2, 82, 8],
+		    [20, 22, 49, 5, 5],
+		    [0, 23, 50, 4, 92],
+  	]
+r = set_cols_rows_to_zero(test2)
+print(r)

others/arrays/sum_2_int_equal_value.py

@@ -0,0 +1,22 @@
+"""
+Given an array of integers and a value, determine if there are any two integers in the array whose sum is equal to the given value. 
+Return true if the sum exists and return false if it does not.
+"""
+
+def sum_of_two_exist(a, value):
+	existing_numbers = set()
+	for n in a:
+		if (value - n) in existing_numbers:
+			return True
+		existing_numbers.add(n)
+	return False
+
+a = [5,7,1,2,8,4,3]
+test = [10,3,20,1,2,7]
+
+for v in test:
+	equal = sum_of_two_exist(a, v)
+	if equal:
+		print("Value {} exist on sum of two ints in array {}".format(v, a))
+	else:
+		print("Value {} DOES NOT exist on sum of two ints in array {}".format(v, a))