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Original file line number Diff line number Diff line change
@@ -0,0 +1,112 @@
3580\. Find Consistently Improving Employees

Medium

Table: `employees`

+-------------+---------+
| Column Name | Type |
+-------------+---------+
| employee_id | int |
| name | varchar |
+-------------+---------+
employee_id is the unique identifier for this table.
Each row contains information about an employee.

Table: `performance_reviews`

+-------------+------+
| Column Name | Type |
+-------------+------+
| review_id | int |
| employee_id | int |
| review_date | date |
| rating | int |
+-------------+------+
review_id is the unique identifier for this table.
Each row represents a performance review for an employee.
The rating is on a scale of 1-5 where 5 is excellent and 1 is poor.

Write a solution to find employees who have consistently improved their performance over **their last three reviews**.

* An employee must have **at least** `3` **review** to be considered
* The employee's **last** `3` **reviews** must show **strictly increasing ratings** (each review better than the previous)
* Use the most recent `3` reviews based on `review_date` for each employee
* Calculate the **improvement score** as the difference between the latest rating and the earliest rating among the last `3` reviews

Return _the result table ordered by **improvement score** in **descending** order, then by **name** in **ascending** order_.

The result format is in the following example.

**Example:**

**Input:**

employees table:

+-------------+----------------+
| employee_id | name |
+-------------+----------------+
| 1 | Alice Johnson |
| 2 | Bob Smith |
| 3 | Carol Davis |
| 4 | David Wilson |
| 5 | Emma Brown |
+-------------+----------------+

performance\_reviews table:

+-----------+-------------+-------------+--------+
| review_id | employee_id | review_date | rating |
+-----------+-------------+-------------+--------+
| 1 | 1 | 2023-01-15 | 2 |
| 2 | 1 | 2023-04-15 | 3 |
| 3 | 1 | 2023-07-15 | 4 |
| 4 | 1 | 2023-10-15 | 5 |
| 5 | 2 | 2023-02-01 | 3 |
| 6 | 2 | 2023-05-01 | 2 |
| 7 | 2 | 2023-08-01 | 4 |
| 8 | 2 | 2023-11-01 | 5 |
| 9 | 3 | 2023-03-10 | 1 |
| 10 | 3 | 2023-06-10 | 2 |
| 11 | 3 | 2023-09-10 | 3 |
| 12 | 3 | 2023-12-10 | 4 |
| 13 | 4 | 2023-01-20 | 4 |
| 14 | 4 | 2023-04-20 | 4 |
| 15 | 4 | 2023-07-20 | 4 |
| 16 | 5 | 2023-02-15 | 3 |
| 17 | 5 | 2023-05-15 | 2 |
+-----------+-------------+-------------+--------+

**Output:**

+-------------+----------------+-------------------+
| employee_id | name | improvement_score |
+-------------+----------------+-------------------+
| 2 | Bob Smith | 3 |
| 1 | Alice Johnson | 2 |
| 3 | Carol Davis | 2 |
+-------------+----------------+-------------------+

**Explanation:**

* **Alice Johnson (employee\_id = 1):**
* Has 4 reviews with ratings: 2, 3, 4, 5
* Last 3 reviews (by date): 2023-04-15 (3), 2023-07-15 (4), 2023-10-15 (5)
* Ratings are strictly increasing: 3 → 4 → 5
* Improvement score: 5 - 3 = 2
* **Carol Davis (employee\_id = 3):**
* Has 4 reviews with ratings: 1, 2, 3, 4
* Last 3 reviews (by date): 2023-06-10 (2), 2023-09-10 (3), 2023-12-10 (4)
* Ratings are strictly increasing: 2 → 3 → 4
* Improvement score: 4 - 2 = 2
* **Bob Smith (employee\_id = 2):**
* Has 4 reviews with ratings: 3, 2, 4, 5
* Last 3 reviews (by date): 2023-05-01 (2), 2023-08-01 (4), 2023-11-01 (5)
* Ratings are strictly increasing: 2 → 4 → 5
* Improvement score: 5 - 2 = 3
* **Employees not included:**
* David Wilson (employee\_id = 4): Last 3 reviews are all 4 (no improvement)
* Emma Brown (employee\_id = 5): Only has 2 reviews (needs at least 3)

The output table is ordered by improvement\_score in descending order, then by name in ascending order.
Original file line number Diff line number Diff line change
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# Write your MySQL query statement below
# #Medium #Database #2025_06_11_Time_449_ms_(91.67%)_Space_0.0_MB_(100.00%)
WITH Ranked AS (
SELECT
e.employee_id,
e.name,
pr.review_date,
pr.rating,
RANK() OVER (
PARTITION BY e.employee_id
ORDER BY pr.review_date DESC
) AS rnk,
LAG(pr.rating) OVER (
PARTITION BY e.employee_id
ORDER BY pr.review_date DESC
) AS lag_rating
FROM employees e
LEFT JOIN performance_reviews pr
ON e.employee_id = pr.employee_id
)
SELECT
employee_id,
name,
MAX(rating) - MIN(rating) AS improvement_score
FROM Ranked
WHERE rnk <= 3
GROUP BY
employee_id,
name
HAVING
COUNT(*) = 3
AND SUM(CASE WHEN lag_rating > rating THEN 1 ELSE 0 END) = 2
ORDER BY
improvement_score DESC,
name ASC;
Original file line number Diff line number Diff line change
@@ -0,0 +1,96 @@
package g3501_3600.s3580_find_consistently_improving_employees

import org.hamcrest.CoreMatchers.equalTo
import org.hamcrest.MatcherAssert.assertThat
import org.junit.jupiter.api.Test
import org.zapodot.junit.db.annotations.EmbeddedDatabase
import org.zapodot.junit.db.annotations.EmbeddedDatabaseTest
import org.zapodot.junit.db.common.CompatibilityMode
import java.io.BufferedReader
import java.io.FileNotFoundException
import java.io.FileReader
import java.sql.SQLException
import java.util.stream.Collectors
import javax.sql.DataSource

@EmbeddedDatabaseTest(
compatibilityMode = CompatibilityMode.MySQL,
initialSqls = [
(
"CREATE TABLE employees(employee_id INTEGER, name VARCHAR(255)); " +
"INSERT INTO employees (employee_id, name) VALUES" +
" (1, 'Alice Johnson')," +
" (2, 'Bob Smith')," +
" (3, 'Carol Davis')," +
" (4, 'David Wilson')," +
" (5, 'Emma Brown');" +
"CREATE TABLE performance_reviews(review_id INTEGER, employee_id INTEGER" +
", review_date DATE, rating INTEGER); " +
"INSERT INTO performance_reviews (review_id, employee_id, review_date, rating) VALUES" +
" (1, 1, '2023-01-15', 2)," +
" (2, 1, '2023-04-15', 3)," +
" (3, 1, '2023-07-15', 4)," +
" (4, 1, '2023-10-15', 5)," +
" (5, 2, '2023-02-01', 3)," +
" (6, 2, '2023-05-01', 2)," +
" (7, 2, '2023-08-01', 4)," +
" (8, 2, '2023-11-01', 5)," +
" (9, 3, '2023-03-10', 1)," +
" (10, 3, '2023-06-10', 2)," +
" (11, 3, '2023-09-10', 3)," +
" (12, 3, '2023-12-10', 4)," +
" (13, 4, '2023-01-20', 4)," +
" (14, 4, '2023-04-20', 4)," +
" (15, 4, '2023-07-20', 4)," +
" (16, 5, '2023-02-15', 3)," +
" (17, 5, '2023-05-15', 2);"
),
],
)
internal class MysqlTest {
@Test
@Throws(SQLException::class, FileNotFoundException::class)
fun testScript(@EmbeddedDatabase dataSource: DataSource) {
dataSource.connection.use { connection ->
connection.createStatement().use { statement ->
statement.executeQuery(
BufferedReader(
FileReader(
(
"src/main/kotlin/g3501_3600/" +
"s3580_find_consistently_improving_employees/" +
"script.sql"
),
),
)
.lines()
.collect(Collectors.joining("\n"))
.replace("#.*?\\r?\\n".toRegex(), ""),
).use { resultSet ->
assertThat<Boolean>(resultSet.next(), equalTo<Boolean>(true))
assertThat<String>(resultSet.getNString(1), equalTo<String>("2"))
assertThat<String>(
resultSet.getNString(2),
equalTo<String>("Bob Smith"),
)
assertThat<String>(resultSet.getNString(3), equalTo<String>("3"))
assertThat<Boolean>(resultSet.next(), equalTo<Boolean>(true))
assertThat<String>(resultSet.getNString(1), equalTo<String>("1"))
assertThat<String>(
resultSet.getNString(2),
equalTo<String>("Alice Johnson"),
)
assertThat<String>(resultSet.getNString(3), equalTo<String>("2"))
assertThat<Boolean>(resultSet.next(), equalTo<Boolean>(true))
assertThat<String>(resultSet.getNString(1), equalTo<String>("3"))
assertThat<String>(
resultSet.getNString(2),
equalTo<String>("Carol Davis"),
)
assertThat<String>(resultSet.getNString(3), equalTo<String>("2"))
assertThat<Boolean>(resultSet.next(), equalTo<Boolean>(false))
}
}
}
}
}