task 3 #3
task 3 #3
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IVAN_MARAKHOVSKII/countDown.js
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| function countDown(n) { | |||
| for (let i = n; i >= 0; i--) { | |||
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Pretty much fine, but do you know another solution to the task without let?
IVAN_MARAKHOVSKII/stringExpansion.js
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| function stringExpansion(str) { | |||
| if (str == "") { | |||
| ans[index] = item.split("").join(spl); | ||
| }); | ||
| return ans.join(spl); | ||
| } |
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Just a note
According to the description - your words should be separated by empty space, not separator you pass in
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What does empty space mean?
from description : "... and then divide each word into characters(Use separator empty string);"
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Good work! |
IVAN_MARAKHOVSKII/convert.js
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| for (let i = 0; i < keys.length; i++) { | ||
| result.push([keys[i],hash[keys[i]]]); | ||
| } | ||
| return result; |
| for (let i = 1 ; i < arguments.length ; i++){ | ||
| if (arguments[i] < min ) min = arguments[i] | ||
| } | ||
| return min |
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There are methods like .largest and .smallest that could be used fir simplicity
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it's undefined when i'm trying to get arguments.smallest() or arguments.smallest
IVAN_MARAKHOVSKII/transform.js
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| function transform(arr) { | |||
| for (let i = 0; i < arr.length; i++) { | |||
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Just a note, you could use map to transform array
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