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stub: cancel Start() for early connection loss. #238
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since we are overloading the cfgErrC is there any chance we end up with two writers to the channel in one Start?
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So if
connClosedwrites tocfgErrcwhileConfigureis running, the deferred send inConfigurewould block forever and leak a goroutine?What if we make the send in
Configurenon-blocking as well? That would ensure whichever function gets there first wins.What do you think?
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I am not sure, because I don't know (and did not try to check/test) how racy a socket connection close soon after a ttrpc message sending over the same socket can end up being wrt. ttrpc delivering the message or an onClose() callback. Therefore I wanted to err on the side of safety, so although cfgErrC is a buffered channel with a capacity of 1, I still decided to do an attempted/non-blocking send here with a select, so we can't get stuck here. If sending here fails, it means that there is already a pending/unreceived cfgErr in the channel, which will nudge Start() out of the wait-receive, so no harm is done if the extra ttrpc.ErrClosed attempted to send here is lost. And if Configure() has not failed yet, or the failure error has not been delivered over the channel yet, sending will succeed as the channel is empty, which again should nudge Start() out of the wait-receive.
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Hmm, I think it shouldn't. The channel is buffered with a capacity of 1. We always read/receive 1 error, sent from Configure() or connClosed(), whichever comes first, and we try to send at most 2. So if we send 2, then 1 stays buffered in the channel, which should not be a problem either, because if the stub is ever re-Start()ed (so we try to go through this again), it creates a new cfgErrC channel.
Yes, I think that is a good idea. I updated the PR accordingly.