Due to a mistake in libcurl's WebSocket code, a malicious...
High severity
Unreviewed
Published
Jun 7, 2025
to the GitHub Advisory Database
•
Updated Jul 30, 2025
Description
Published by the National Vulnerability Database
Jun 7, 2025
Published to the GitHub Advisory Database
Jun 7, 2025
Last updated
Jul 30, 2025
Due to a mistake in libcurl's WebSocket code, a malicious server can send a
particularly crafted packet which makes libcurl get trapped in an endless
busy-loop.
There is no other way for the application to escape or exit this loop other
than killing the thread/process.
This might be used to DoS libcurl-using application.
References