Skip to content

Update README.md #1293

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 1 commit into from
Aug 13, 2024
Merged
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
51 changes: 23 additions & 28 deletions README.md
Original file line number Diff line number Diff line change
Expand Up @@ -262,41 +262,58 @@ $\lim_{x \to -\infty} (2x^4 - 3x^3 + x + 6) = \infty$

Even though ( x ) is negative, y.


#

## These processes above demonstrates how limits help us understand the behavior of functions near points that might not be defined, by finding equivalent expressions that are easier to evaluate.
## [3.Calculate the Following Limits]()

<br>
### 3a: Finding the limit of a polynomial function as x approaches infinity

###### <p align="center"> [Copyright 2024 Quantum Software Development. Code released under the MIT License license.](https://github.com/Quantum-Software-Development/Math/blob/3bf8270ca09d3848f2bf22f9ac89368e52a2fb66/LICENSE)
The given function is a polynomial function of the form:

$$f(x)=axn+bxn−1+cxn−2+...+dx+e$$

<br>

As x approaches infinity, the highest power of x in the function dominates the value of the function. This means that we can ignore all the lower-order terms, and simply consider the behavior of the highest-order term.
In this case, the highest-order term is 2x4. As x approaches infinity, x4 also approaches infinity, and so the function f(x) also approaches infinity.

Therefore, the limit of the function as x approaches infinity is infinity. We can write this mathematically as:

$$x→∞lim x32x4−3x3+x+6 =0$$

#

### 3b:Finding the limit of a rational function as x approaches infinity


The given function is a rational function of the form

$$f(x)=cxm+fxm−1+...+gx+haxn+bxn−1+...+dx+e$$

<br>

, where n > m. As x approaches infinity, the highest power of x in the numerator dominates the value of the numerator, and the highest power of x in the denominator dominates the value of the denominator. This means that we can ignore all the lower-order terms, and simply consider the behavior of the highest-order terms.

In this case, the highest-order term in the numerator is 2x4, and the highest-order term in the denominator is x3.

As x approaches infinity, 2x4 grows much faster than x3, and so the function f(x) approaches zero.

#

### These processes above demonstrates how limits help us understand the behavior of functions near points that might not be defined, by finding equivalent expressions that are easier to evaluate.

#

###### <p align="center"> [Copyright 2024 Quantum Software Development. Code released under the MIT License license.](https://github.com/Quantum-Software-Development/Math/blob/3bf8270ca09d3848f2bf22f9ac89368e52a2fb66/LICENSE)













Expand All @@ -310,47 +327,25 @@ Even though ( x ) is negative, y.



<!--
<br><br>

## 3.Calculate the Following Limits

### 3a: Finding the limit of a polynomial function as x approaches infinity

The given function is a polynomial function of the form:

<br>

$$f(x)=axn+bxn−1+cxn−2+...+dx+e$$

As x approaches infinity, the highest power of x in the function dominates the value of the function. This means that we can ignore all the lower-order terms, and simply consider the behavior of the highest-order term.
In this case, the highest-order term is 2x4. As x approaches infinity, x4 also approaches infinity, and so the function f(x) also approaches infinity.

Therefore, the limit of the function as x approaches infinity is infinity. We can write this mathematically as:

<br>

$$x→∞lim x32x4−3x3+x+6 =0$$

#

### 3b:Finding the limit of a rational function as x approaches infinity

<br>

The given function is a rational function of the form

<br>

$$f(x)=cxm+fxm−1+...+gx+haxn+bxn−1+...+dx+e$$

<br>

, where n > m. As x approaches infinity, the highest power of x in the numerator dominates the value of the numerator, and the highest power of x in the denominator dominates the value of the denominator. This means that we can ignore all the lower-order terms, and simply consider the behavior of the highest-order terms.

In this case, the highest-order term in the numerator is 2x4, and the highest-order term in the denominator is x3.

As x approaches infinity, 2x4 grows much faster than x3, and so the function f(x) approaches zero.



Expand Down