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0x19. C - Stacks, Queues - LIFO, FIFO🤝TEAM PROJECT🤝

This directory contains files that can be tested for C - Stacks, Queues - LIFO, FIFO.

📁 : monty.h - This is a header file that contains all prototypes for functions written for the project.

Tasks

Tip

Compile with the following GCC flags:

    gcc -Wall -Werror -Wextra -pedantic -std=gnu89 *.c -o monty

0. push, pall

Implement the push and pall opcodes.

The push opcode
The opcode push pushes an element to the stack.

  • Usage : push <int>
    • where <int> is an integer
  • if <int> is not an integer or if there is no argument given to push, print the error message L<line_number>: usage: push integer, followed by a new line, and exit with the status EXIT_FAILURE
    • where is the line number in the file
  • You won't have to deal with overflows. Use the atoi function

The pall opcode
The opcode pall prints all the values on the stack, starting from the top of the stack.

  • Usage pall
  • If the stack is empty, don't print anything

1. pint

Implement the pint opcode.

The pint opcode
The opcode pint prints the value at the top of the stack, followed by a new line.

  • Usage; pint
  • If the stack is empty, print the error message L<line_number>: can't pint, stack empty, followed by a new line, and exit with the status EXIT_FAILURE

2. pop

Implement the pop opcode.

The pop opcode
The opcode pop removes the top element of the stack.

  • Usage: pop
  • If the stack is empty, print the error message L<line_number>: can't pop an empty stack, followed by a new line, and exit with the status EXIT_FAILURE

3. swap

Implement the swap opcode.

The swap opcode
The opcode swap swaps the top two elements of the stack.

  • Usage: swap
  • If the stack contains less than two elements, print the error message L<line_number>: can't swap, stack too short, followed by a new line, and exit with the status EXIT_FAILURE

4. add

Implement the add opcode

The add opcode
The opcode add adds the top two elements of the stack.

  • Usage: add
  • If the stack contains less than two elements, print the error message L<line_number>: can't add, stack too short, followed by a new line, and exit with the status EXIT_FAILURE
  • The result is stored in the second top element of the stack, and the top element is removed, so that at the end:
    • The top element of the stack contains the result
    • The stack is one element shorter

5. nop

Implement the nop opcode.

The nop opcode
The opcode nop doesn’t do anything.

  • Usage: nop

6. sub🔥advanced task🔥

Implement the sub opcode.

The sub opcode
The opcode sub subtracts the top element of the stack from the second top element of the stack.

  • Usage: sub
  • If the stack contains less than two elements, print the error message L<line_number>: can't sub, stack too short, followed by a new line, and exit with the status EXIT_FAILURE
  • The result is stored in the second top element of the stack, and the top element is removed, so that at the end:
    • The top element of the stack contains the result
    • The stack is one element shorter

7. div🔥advanced task🔥

Implement the div opcode.

The div opcode
The opcode div divides the second top element of the stack by the top element of the stack

  • Usage: div
  • If the stack contains less than two elements, print the error message L<line_number>: can't dive, stack too short, followed by a new line, and exit with the status EXIT_FAILURE
  • The result is stored in the second top element of the stack, and the top element is removed, so that at the end:
    • The top element of the stack contains the result
    • The stack is one element shorter
  • If the top element of the stack is 0, print the error message L<line_number>: division by zero, followed by a new line, and exit with the status EXIT_FAILURE

8. mul🔥advanced task🔥

Implement the mul opcode.

The mul opcode
The opcode mul multiples the second top element of the stack with the top element of the stack.

  • Usage: mul
  • If the stack contains less than two elements, print the error message L<line_number>: can't mul, stack too short, followed by a new line, and exit with the status EXIT_FAILURE
  • The result is stored in the second top element of the stack, and the top element is removed, so that at the end:
    • The top element of the stack contains the result
    • The stack is one element shorter

9. mod🔥advanced task🔥

Implement the mod opcode.

The mod opcode
The opcode mod computes the rest of the division of the second element of the stack by the top element of the stack.

  • Usage: mod
  • If the stack contains less than two elements, print the error message L<line_number>: can't mod, stack too short, followed by a new line, and exit with the status EXIT_FAILURE
  • The result is stored in the second top element of the stack, and the top element is removed, so that at the end:
    • The top element of the stack contains the result
    • The stack is one element shorter
  • If the top element of the stack is 0, print the error message L<line_number>: division by zero, followed by a new line, and exit with the status EXIT_FAILURE

10. comments🔥advanced task🔥

Every good language comes with the capability of commenting. When the first non-space character of a line is #, treat this line as a comment (don't do anything).

11. pchar🔥advanced task🔥

Implement the pchar opcode

The pchar opcode The opcode pchar prints the char at the top of the stack, followed by a new line.

  • Usage: pchar
  • The integer stored at the top of the stack is treated as the ascii value of the character to be printed
  • If the value is not in the ascii table (man ascii) print the error message L<line_number>: can't pchar, value out of range, followed by a new line, and exit with the status EXIT_FAILURE
  • If the stack is empty, print the error message L<line_number>: can't pchar, stack empty, followed by a new line, and exit with the status EXIT_FAILURE

12. pstr🔥advanced task🔥

Implement the pstr opcode.

The pstr opcode
The opcode pstr prints the string starting at the top of the stack, followed by a new line.

  • Usage: pstr
  • The integer stored in each element of the stack is treated as the ascii value character of the character to be printed
  • The string stops when either:
    • the stack is over
    • the value of the element is 0
    • the value of the element is not in the ascii table
  • If the stack is empty, print only a new line

13. rot1🔥advanced task🔥

Implement the rot1 opcode.

The rot1 opcode The opcode rot1 rotates the stack to the top.

  • Usage: rot1
  • The top element of the stack becomes the last one, and the second top element of the stack becomes the first one
  • rot1 never fails

14. rotr🔥advanced task🔥

Implement the rotr opcode.

The rotr opcode
The opcode rotr rotates the stack to the bottom.

  • Usage: rotr
  • The last element of the stack becomes the top element of the stack
  • rotr never fails

15. stack, queue🔥advanced task🔥

Implement the stack and queue opcodes.

The stack opcode
The opcode stack sets the format of the data to a stack (LIFO). This is the default behavior of the program.

  • Usage: stack

The queue opcode
The opcode queue sets the format of the data to a queue (FIFO).

  • Usage: queue

When switching mode:

  • The top of the stack becomes the front of the queue
  • The front of the queue becomes the top of the stack

16. Brainf*ck🔥advanced task🔥

Write a Brainf*ck script that prints School, followed by a new line.

  • All your Brainf*ck files, should be stored inside the bf sub directory
  • You can install the bf interpreter to test your code: sudo apt-get install bf
  • 📁 1000-school.bf

17. Add two digits🔥advanced task🔥

Add two digits given by the user.

  • Read the two digits from stdin, add them, and print the result
  • The total of the two digits will be one digit-long(<10)
  • 📁 1001-add.bf

18. Multiplication🔥advanced task🔥

Multiply two digits given by the user.

  • Read the two digits from stdin, multiply them, and print the result
  • The result of the multiplication will be one digit-long(<10)
  • 📁 1002-mul.bf

19. Multiplication level up🔥advanced task🔥

Multiply two digits given by the user.

  • Read the two digits from stdin, multiply them, and print the result, followed by a new line
  • 📁 1003-mul.bf

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