feat: determine namespace from testcase name and provide it as variable

Author: dervoeti

src/beku/kuttl.py

@@ -7,6 +7,7 @@
 import re
 from dataclasses import dataclass, field
 from functools import cached_property
+from hashlib import sha256
 from itertools import product, chain
 from os import walk, path, makedirs
 from shutil import copy2
@@ -132,6 +133,7 @@ def expand(self, template_dir: str, target_dir: str) -> None:
         _mkdir_ignore_exists(tc_root)
         test_env = Environment(loader=FileSystemLoader(path.join(template_dir, self.name)), trim_blocks=True)
         test_env.globals["lookup"] = ansible_lookup
+        test_env.globals["NAMESPACE"] = determine_namespace(self.tid)
         sub_level: int = 0
         for root, dirs, files in walk(td_root):
             sub_level += 1
@@ -328,6 +330,11 @@ def expand(
     return 0
 
 
+def determine_namespace(testcase_name: str) -> str:
+    hash = sha256(testcase_name.encode("utf-8")).hexdigest()
+    return f"kuttl-{testcase_name[:32]}-{hash[:10]}"
+
+
 def _expand_kuttl_tests(test_cases, output_dir: str, kuttl_tests: str) -> None:
     """Generate the kuttl-tests.yaml file and fill in paths to tests."""
     env = Environment(loader=FileSystemLoader(path.dirname(kuttl_tests)))

src/beku/version.py

@@ -1,3 +1,3 @@
 """Package version."""
 
-__version__ = "0.0.9"
+__version__ = "0.0.10"