feat: determine namespace from testcase name and provide it as variable

Author: dervoeti

src/beku/kuttl.py

@@ -6,6 +6,7 @@
 import re
 from dataclasses import dataclass, field
 from functools import cached_property
+from hashlib import sha256
 from itertools import product, chain
 from os import walk, path, makedirs
 from shutil import copy2
@@ -128,6 +129,7 @@ def expand(self, template_dir: str, target_dir: str) -> None:
             trim_blocks=True
         )
         test_env.globals['lookup'] = ansible_lookup
+        test_env.globals['NAMESPACE'] = determine_namespace(self.tid)
         sub_level: int = 0
         for root, dirs, files in walk(td_root):
             sub_level += 1
@@ -320,6 +322,9 @@ def expand(suite: str, effective_test_suites: List[EffectiveTestSuite], template
             f"Cannot expand test suite [{suite}] because cannot find it in [{kuttl_tests}]") from exc
     return 0
 
+def determine_namespace(testcase_name: str) -> str:
+    hash = sha256(testcase_name.encode('utf-8')).hexdigest()
+    return f"kuttl-{testcase_name[:32]}-{hash[:10]}"
 
 def _expand_kuttl_tests(test_cases, output_dir: str, kuttl_tests: str) -> None:
     """Generate the kuttl-tests.yaml file and fill in paths to tests."""

src/beku/version.py

@@ -1,2 +1,2 @@
 """Package version."""
-__version__ = "0.0.9"
+__version__ = "0.0.10"