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Saviour1001Saviour1001
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Merge pull request #690 from Mayuri-cell/master
Arithmetic , Geometric progression .
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‎Arrays/Missing_integer.cpp

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/* Title : User will enter the unsorted array .
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You will need to sort it and has to
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find out the first missing positive integer from the sorted array .
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*/
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#include<iostream>
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#include<math.h>
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#include<stdlib.h>
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using namespace std;
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int main()
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{
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int n ,j=0, i,k=1 , val;
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cout<<" Enter the total number of elements "<<endl;
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cin>>n;
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int a[n];
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cout<<" Enter the elements : \n"<<endl;
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for(i=0;i<n;i++)
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{ cin>>a[i]; }
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for(i=0;i<n;i++)
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{ for(j=0;j<n-1;j++)
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if(a[j]>a[j+1])
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{ val=a[j];
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a[j]=a[j+1];
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a[j+1]=val; }
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}
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cout<<" Sorted array : \n"<<endl;
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for(i=0;i<n;i++)
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{
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cout<<a[i]<<" ";
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}
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cout<<" \n"<<endl;
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cout<<" Missing element : ";
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if(a[n-1]<=0)
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{
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cout<<"1";
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}
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else {
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for(i=0;i<n;i++)
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{
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if(a[i]>0)
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{
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for(j=0+i, k=1;j<=n && k<=n+1;k++,j++)
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{
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if(a[j]==k)
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{
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continue ;
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}
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else
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{
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cout<<k;
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exit(0);
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} }
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} }
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}}
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/*
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Enter the total number of elements
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5
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Enter the elements :
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12
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-43
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-5
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0
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2
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Sorted array :
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-43 -5 0 2 12
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Missing element : 1
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*/

‎General Questions/AP_GP.cpp

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/* Title : To find whether the given series format is following AP or GP .
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Description : User need to provide the terms present and also need to mention
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how many number of terms user is providing .
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You can also find the ' Mean' , ' Sum ' and the nth the term if
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it is following any one of the of progression .
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Need to enter atleast three minimun number .
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***** For A.P and G.P , here the common difference , common ratio should be greater than 1 .******
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*/
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#include<iostream>
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#include<stdlib.h>
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#include<math.h>
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using namespace std ;
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int main()
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{ int opt ;
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float s;
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cout<<" **** Welcome *** "<<endl;
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cout<<" Arithematic Progression : Common difference between two adjacent terms is constant ."<<endl;
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cout<<" Geometric Progression : Common ratio between two adjacent terms is constant .\n( For G.P here we can perform the operations for common difference greater than 1 only.) \n "<<endl;
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do
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{
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int i=0,j=0 ,n ;
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float sum=0, mean ,nth ,d ,k, s=1;
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float first_term, AP ,GP;
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int count=1 , co=0;
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cout<<"\n Enter the number elements of the given series you wish to enter : \n **** You need to enter atleast 3 terms **** \n"<<endl; /* User need tor provide minimum three terms . Otherwise system will exit */
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cin>>n;
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float a[n];
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cout<<"\n Enter the elements : \n"<<endl;
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for(i=0;i<n;i++)
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{ cin>>a[i] ; }
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AP=a[1]-a[0];
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GP=a[1]/a[0];
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first_term=a[0];
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// To define the operation of A.P and G,P:
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for(i=0;i<n-1;i++)
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{
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// a. AP operations :
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d=a[i+2]-a[i+1];
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if (AP==d)
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{ count++ ;
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if (count==n-1)
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{
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do {
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cout<<"\n Given series is in Arithematic Progression " <<endl;
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cout<<"\n 1.Mean \n 2.Sum \n 3.To find the nth element of the given series \n 4.Exit : "<<endl;
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cin>>opt;
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switch(opt)
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{
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case 1 : cout<<"\n Mean of the given A.P series : "<<endl;
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i=0 , sum=0;
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while(i<n)
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{
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sum=sum+a[i];
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i++;
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}
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mean=sum/n;
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cout<<" Arithematic Mean : "<<mean<<endl;
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break ;
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case 2 :
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cout<<"\n Sum of the first "<< n<< " AP elements entered : "<<endl;
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sum=0;
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sum=(n*((2*first_term) + (n - 1)*(AP)))/2;
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cout<<sum<<endl;
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break ;
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case 3 : cout<<" Enter the nth element : "<<endl;
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cin>>nth;
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nth= (first_term + (nth - 1)*AP );
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cout<<" Nth element of the given AP : "<<nth<<endl;
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break ;
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case 4 : exit(0);
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break ;
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default : cout<<"\n Invalid option , Try again later !"<<endl;
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break;
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}
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cout<<"\n Wish to continue the AP operations on the given series ?\n1.Yes 2.No \n"<<endl; /* 1. To continue or press any to stop */
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cin>>opt;
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}while(opt==1);
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}
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}
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}
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//2.GP Operations :
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for(i=0;i<n-2;i++)
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{
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// a. AP operations :
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d=a[i+2]/a[i+1];
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if (GP==d)
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{ co++ ;
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if(co==n-2)
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{
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do
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{
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cout<<" \n Given series is in Geometric Progression " <<endl;
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cout<<"\n 1.Mean \n 2.Sum \n 3.To find the nth element of the given series \n 4.Exit : "<<endl;
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cin>>opt;
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switch(opt)
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{
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case 1 : cout<<"\n Enter the number of elements to find the geometric mean : \n"<<endl;
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float t;
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cin>>t;
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cout<<"\n the first "<<t<<" given G.P series elements have the "<<endl;
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i=0;
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while(i<n)
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{
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s=s*a[i];
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i++; }
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mean=pow(s, (1/t));
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cout<<" Geometrical Mean : "<<mean<<endl;
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break ;
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case 2 : cout<<"Enter the number of elements to find the mean of them : "<<endl;
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int tt;
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cin>>tt;
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cout<<"\n Sum of the first "<<tt<<"GP elements : "<<endl;
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sum=first_term*((pow(GP, tt))-1)/(GP-1);
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cout<<abs(sum)<<endl;
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cout<<" If the series belongs to infinity : "<<endl;
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cout<<" sum : "<<abs(first_term/(1 - GP))<<endl;
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break ;
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case 3 : cout<<" Enter the nth element : "<<endl;
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cin>>nth;
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nth=first_term*pow(GP , nth-1);
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cout<<" Nth term of the given G.P : "<<nth<<endl;
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break ;
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case 4 : exit(0);
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break ;
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default : cout<<"\n Invalid option , Try again later !"<<endl;
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break;
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}
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cout<<" \n Wish to continue the GP operations on the given series ?\n1.Yes 2.No \n"<<endl; /* 1. To continue or press any to stop */
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cin>>opt;
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}while(opt==1);
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}
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}
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}
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cout<<"\n Do you wish to continue further or not \n1.Yes 2.No \n"<<endl; /* 1. To continue or press any to stop */
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cin>>opt;
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} while(opt==1);
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}
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/*
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**** Welcome ***
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Arithematic Progression : Common difference between two adjacent terms is constant .
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Geometric Progression : Common ratio between two adjacent terms is constant .
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Enter the number elements of the given series you wish to enter :
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**** You need to enter atleast 3 terms ****
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3
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Enter the elements :
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1
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1.02
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1.04
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Given series is in Arithematic Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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1
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Mean of the given A.P series :
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Arithematic Mean : 1.02
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Wish to continue the AP operations on the given series ?
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1.Yes 2.No
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1
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Given series is in Arithematic Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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2
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Sum of the first 3 AP elements entered :
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3.06
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Wish to continue the AP operations on the given series ?
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1.Yes 2.No
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1
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Given series is in Arithematic Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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3
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Enter the nth element :
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5
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Nth element of the given AP : 1.08
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Wish to continue the AP operations on the given series ?
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1.Yes 2.No
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2
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Do you wish to continue further or not
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1.Yes 2.No
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1
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Enter the number elements of the given series you wish to enter :
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**** You need to enter atleast 3 terms ****
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4
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Enter the elements :
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2
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4
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8
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16
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Given series is in Geometric Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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1
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Enter the number of elements to find the geometric mean :
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4
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the first 4given G.P series elements have the
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Geometrical Mean : 5.65685
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Wish to continue the GP operations on the given series ?
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1.Yes 2.No
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1
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Given series is in Geometric Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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2
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Enter the number of elements to find the mean of them :
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3
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Sum of the first 3 GP elements :
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14
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If the series belongs to infinity :
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sum : 2
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Wish to continue the GP operations on the given series ?
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1.Yes 2.No
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1
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Given series is in Geometric Progression
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1.Mean
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2.Sum
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3.To find the nth element of the given series
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4.Exit :
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3
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Enter the nth element :
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5
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Nth term of the given G.P : 32
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Wish to continue the GP operations on the given series ?
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1.Yes 2.No
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2
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Do you wish to continue further or not
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1.Yes 2.No
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2
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*/

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