Create Richie Rich.c

Author: simranquirky

Codechef Problems/Richie Rich.c

@@ -0,0 +1,58 @@
+/* Chef aims to be the richest person in Chefland by his new restaurant franchise. Currently, his assets are worth A billion dollars and have no liabilities. He aims to increase his assets by X billion dollars per year.
+
+Also, all the richest people in Chefland are not planning to grow and maintain their current worth.
+
+To be the richest person in Chefland, he needs to be worth at least B billion dollars. How many years will it take Chef to reach his goal if his value increases by X billion dollars each year?
+
+Input
+The first line contains an integer T, the number of test cases. Then the test cases follow.
+Each test case contains a single line of input, three integers A, B, X.
+Output
+For each test case, output in a single line the answer to the problem.
+
+Constraints
+1≤T≤21 000
+100≤A<B≤200
+1≤X≤50
+X divides B−A
+
+Sample Input
+3
+100 200 10
+111 199 11
+190 200 10
+Sample Output
+10
+8
+1
+Explanation
+Test Case 1: Chef needs to increase his worth by 200−100=100 billion dollars and his increment per year being 10 billion dollars, so it will take him 10010=10 years to do so.
+
+Test Case 2: Chef needs to increase his worth by 199−111=88 billion dollars and his increment per year being 11 billion dollars, so it will take him 8811=8 years to do so.
+
+Test Case 3: Chef needs to increase his worth by 200−190=10 billion dollars and his increment per year being 10 billion dollars, so it will take him 1010=1 year to do so. */
+
+
+#include <stdio.h>
+
+int main(void) {
+	
+	int t,a,b,x;
+	scanf("%d",&t);
+	
+	int i;int time[t-1];
+	for(i=0;i<t;i++)
+	{
+	    scanf("%d %d %d",&a,&b,&x);
+	    time[i]=(b-a)/x;
+	    
+	}
+		for(i=0;i<t;i++)
+	{
+	    
+	    printf("%d\n",time[i]);
+	    
+	}
+	
+	return 0;
+}