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+ /*
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+ Given a non-negative integer N. The task is to check if N is a power of 2. More formally, check if N can be expressed as 2x for some x.
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+
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+
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+ Example 1:
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+
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+ Input: N = 1
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+ Output: true
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+ Explanation:
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+ 1 is equal to 2 raised to 0 (20 = 1).*/
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+ // Initial Template for C++
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+
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+ #include < bits/stdc++.h>
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+ using namespace std ;
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+
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+ // Function to check power of two
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+ bool isPowerofTwo (long long n){
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+
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+ // Your code here
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+ if (n==0 )
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+ return 0 ;
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+
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+ else if (n>0 )
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+ {
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+ if ((n & n-1 )==0 )
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+ return 1 ;
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+ }
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+ return 0 ;
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+ }
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+
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+ // Driver code
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+ int main ()
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+ {
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+
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+ int t;
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+ cin>>t;// testcases
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+
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+ for (int i=0 ;i<t;i++)
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+ {
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+ long long n; // input a number n
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+ cin>>n;
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+
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+ if (isPowerofTwo (n))// Now, if log2 produces an integer not decimal then we are sure raising 2 to this value
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+ cout<<" YES" <<endl;
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+ else
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+ cout<<" NO" <<endl;
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+
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+ }
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+
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+ return 0 ;
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+ }
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+ // } Driver Code Ends
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