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run_local not working on windows #411

@jacobEAdamson

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@jacobEAdamson

My system is Python 3.7.0 running Windows 10 and I receive an error when I try to run anything with run_local on windows (which affects all backends). The stack trace looks like this:

venv\lib\site-packages\testinfra\host.py:71: in run
    return self.backend.run(command, *args, **kwargs)
venv\lib\site-packages\testinfra\backend\docker.py:35: in run
    "docker exec %s /bin/sh -c %s", self.name, cmd)
venv\lib\site-packages\testinfra\backend\base.py:203: in run_local
    stderr=subprocess.PIPE,
..\..\..\appdata\local\programs\python\python37-32\Lib\subprocess.py:756: in __init__
    restore_signals, start_new_session)
..\..\..\appdata\local\programs\python\python37-32\Lib\subprocess.py:1100: in _execute_child
    args = list2cmdline(args)
..\..\..\appdata\local\programs\python\python37-32\Lib\subprocess.py:511: TypeError
    TypeError: argument of type 'int' is not iterable

Looks like the fact that the command is being encoded before running is to blame. Popen in Windows doesn't handle byte arrays the same way it does on Linux. Was able to fix by modifying code to this:

def run_local(self, command, *args):
    command = self.quote(command, *args)
    if os.name != 'nt':
        command = self.encode(command)
    p = subprocess.Popen(
        command, shell=True,
        stdin=subprocess.PIPE,
        stdout=subprocess.PIPE,
        stderr=subprocess.PIPE,
    )
    stdout, stderr = p.communicate()
    result = self.result(p.returncode, command, stdout, stderr)
    return result

Basically only encode when not on windows

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