Skip to content

Handling Time Coordinates #6513

Answered by dcherian
rajatjoshi49266u asked this question in Q&A
Discussion options

You must be logged in to vote

You could try ds["time"] = ds.time - pd.Timedelta("3H") to subtract 3 hours (or some other offset) from the time vector IF that makes sense.

Replies: 1 comment 1 reply

Comment options

You must be logged in to vote
1 reply
@rajatjoshi49266u
Comment options

Answer selected by rajatjoshi49266u
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Category
Q&A
Labels
None yet
2 participants