func == / eq fails w/ Int64 properties

[wildthink]

Description

Given:

@Table
struct User {
    var id: Int64
    var name: String
}

let q = User.where { $0.id == 1 } // <-- Error w/ Int64 but NOT Int

Referencing operator function '==' on 'BinaryInteger' requires that 'TableColumn<User.TableColumns.QueryValue, Int64>' (aka 'TableColumn<User, Int64>') conform to 'BinaryInteger'

Checklist

• I have determined whether this bug is also reproducible in a vanilla SwiftUI project.
• If possible, I've reproduced the issue using the main branch of this package.
• This issue hasn't been addressed in an existing GitHub issue or discussion.

Expected behavior

No response

Actual behavior

No response

Reproducing project

No response

Structured Queries version information

No response

Destination operating system

No response

Xcode version information

No response

Swift Compiler version information

[stephencelis]

@wildthink This is sadly a limitation of Swift and would need to be addressed in the language. Swift's integer literal inference does not extend beyond Int in protocolized contexts like our expression builder.

To work around the issue you must explicitly tell Swift what type of integer you are dealing with:

let q = User.where { $0.id == Int64(1) }
// or
let q = User.where { $0.id == 1 as Int64 }

Since this isn't a bug we can address in the library I'm going to convert to a discussion.

[stephencelis]

FWIW we could maybe introduce an overload on == and eq that could help here when it comes to integer literals, but also we're not sure integer literals are common in actual expressions here. Typically you'll have an Int64 already around and not a compile-time constant ID:

let q = User.where { $0.id == currentUserID }