Nitrite/Java: NitriteId manual creation

[tmoliveira]

Hello,

I would like to create my self the nitriteId but it seems it is not possible. As far as I understood, it is not possible because the toString of the NitrideId is not a String representing the underlying long value.

What I am trying to do is (1) annotating the NitriteId field of my object with @id; (2) creating manually the nitriteId for each on of my objects; (3) implementing the Mappable interface to transform the object in a document, and vice-versa; (4) put in the document the key "_id" with the value NitriteId. However, it fails in this if internal code: $if (DOC_ID.contentEquals(key) && !validId(value)) $ because inside the validId(value) method it gets the toString of the value, which in this case is the toString of an NitriteId object, and this does not return just the long value as a String.

Is there a way that allows me to have the NitriteId directly as a @id while I am responsible for generating this id?

Thanks

[anidotnet]

Hi @tmoliveira, you can capture the auto-generated NitriteId in your object by annotating the field with @Id. But you cannot create your own nitrite id, as it's forbidden by design.

[tmoliveira]

Hi @anidotnet,

Thanks for answering so fast. What I really need is to have the NitriteId before making the insert on the repository. That is why I was trying to create my own NitriteId (e.g., System.nanoTime()). Is there any way to do that? I mean creating the nitriteId before making the insert?

Thanks again @anidotnet,
Regards.

[anidotnet]

Unfortunately no. As I said, it is as it is by design. User does not have any control over NitriteId generation.

[anidotnet]

You can define your own unique id and use that, treat it like NitriteId does not exists.

[tmoliveira]

I already have thought on that. However, in that way I am increasing the latency for insert/get/update as my own unique Id will be an index and not the real object key. The object key will be the auto-generated NitriteId. Is this correct, or am I missing something?

[anidotnet]

Yes your assumption is correct.