Fix link name reference if content type is invalid

marcus-crane · marcus-crane · commit a2e33c166db1 · 2021-04-01T18:48:13.000+13:00
Currently, the name of a custom link is referenced
as if it is an object attribute which causes a break
due to it actually being a dictionary.

This minor change means that the startup script won't
*ahem* fail upon failing :)

Signed-Off-by: Marcus Crane &lt;marcus.crane@daimler.com&gt;
diff --git a/startup_scripts/280_custom_links.py b/startup_scripts/280_custom_links.py
@@ -23,7 +23,7 @@ def get_content_type_id(content_type):
     if link["content_type_id"] is None:
         print(
             "⚠️ Unable to create Custom Link '{0}': The content_type '{1}' is unknown".format(
-                link.name, content_type
+                link.get('name'), content_type
             )
         )
         continue

Original file line number	Diff line number	Diff line change
`@@ -23,7 +23,7 @@ def get_content_type_id(content_type):`
`23`	`23`	`if link["content_type_id"] is None:`
`24`	`24`	`print(`
`25`	`25`	`"⚠️ Unable to create Custom Link '{0}': The content_type '{1}' is unknown".format(`
`26`		`- link.name, content_type`
	`26`	`+ link.get('name'), content_type`
`27`	`27`	`)`
`28`	`28`	`)`
`29`	`29`	`continue`