Physical size of domain

[RasoulNajafi]

Hi all,

I am new to use Neper. Maybe this question has a simple answer. I would appreciate if you help me to find an answer for it.
I use the following command in order to create RVE:

neper -T -n 350 -id 1 -domain ''cube(1,1,1)'' -periodicity all -morpho '' diameq:lognormal(1,0.1),aspratio(2.2,1,1)''

As you can see I have to normalize the dimension of the real RVE into a cube with edge length of 1. In my project, it is quite necessary to have a physical dimension of the generated RVE as well. I tried to use statistics in order to obtain the equivalent diameter of the RVE located on the edge. I use the following code in tesselation module:

'' -statcell id,diameq''

The problem is, the values I obtain is also normalized. I also used the code above without ''cube(1,1,1)'' command and the values were also normalized and I didnt have the real grains equivalent diameter.

My question is how I can extract the physical dimension of the RVE based on the input data. Is there anyway to directly measure the real length of the RVE edge? and how I can find the id number of the elements located on the edge?

Many thanks in advance
Rasoul

[rquey]

If you provide the domain size and the number of grains, then the average grain size (the average value of the lognormal) will be interpreted as a relative value.

If you provide the domain size and -n from_morpho for the number of grains, then the average grain size (the average value of the lognormal) will be interpreted as an absolute value, and the number of grains will be determined accordingly.

There is no equivalent of from_morpho for the domain, but in your case, you typically have to provide absolute values to -morpho (as in morpho "diameq:lognormal(0.01,0.001),..."), -n from_morpho, and adjust the domain size (as in -domain "cube(0.1,0.1,0.1)").