diff --git a/Contributors.md b/Contributors.md
index bb585a2..fa5b727 100644
--- a/Contributors.md
+++ b/Contributors.md
@@ -38,3 +38,4 @@
 * [Muskan](https://github.com/Muskan-goyal6)
 * [Tarannum](https://github.com/giTan7)
 * [HCamberos](https://github.com/HCamberos)
+* [Ankit Bhadage](https://github.com/Ankitmb125)
diff --git a/Dynamic Programming/floydWarshall.cpp b/Dynamic Programming/floydWarshall.cpp
new file mode 100644
index 0000000..dbe917b
--- /dev/null
+++ b/Dynamic Programming/floydWarshall.cpp	
@@ -0,0 +1,61 @@
+/*The Floyd Warshall Algorithm is for solving the All Pairs Shortest Path problem. The problem is to find shortest distances between every pair of vertices in a given edge weighted directed Graph.*/
+
+#include <bits/stdc++.h> 
+using namespace std; 
+  
+#define V 4  
+  
+#define INF 99999  
+  
+void printSolution(int dist[][V]);  
+
+void floydWarshall (int graph[][V])  
+{  
+    int dist[V][V], i, j, k;  
+  
+    for (i = 0; i < V; i++)  
+        for (j = 0; j < V; j++)  
+            dist[i][j] = graph[i][j];  
+    for (k = 0; k < V; k++)  
+    {   
+        for (i = 0; i < V; i++)  
+        {  
+            for (j = 0; j < V; j++)  
+            {  
+                if (dist[i][k] + dist[k][j] < dist[i][j])  
+                    dist[i][j] = dist[i][k] + dist[k][j];  
+            }  
+        }  
+    }  
+  
+    printSolution(dist);  
+}  
+  
+void printSolution(int dist[][V])  
+{  
+    cout<<"The following matrix shows the shortest distances"
+            " between every pair of vertices \n";  
+    for (int i = 0; i < V; i++)  
+    {  
+        for (int j = 0; j < V; j++)  
+        {  
+            if (dist[i][j] == INF)  
+                cout<<"INF"<<"     ";  
+            else
+                cout<<dist[i][j]<<"     ";  
+        }  
+        cout<<endl;  
+    }  
+}  
+  
+int main()  
+{  
+    int graph[V][V] = { {0, 5, INF, 10},  
+                        {INF, 0, 3, INF},  
+                        {INF, INF, 0, 1},  
+                        {INF, INF, INF, 0}  
+                    };  
+  
+    floydWarshall(graph);  
+    return 0;  
+}  
\ No newline at end of file
diff --git a/Dynamic Programming/lis.cpp b/Dynamic Programming/lis.cpp
new file mode 100644
index 0000000..1e484a5
--- /dev/null
+++ b/Dynamic Programming/lis.cpp	
@@ -0,0 +1,31 @@
+/*
+The Longest Increasing Subsequence (LIS) problem is to find the length of the longest subsequence of a given sequence such that all elements of the subsequence are sorted in increasing order. For example, the length of LIS for {10, 22, 9, 33, 21, 50, 41, 60, 80} is 6 and LIS is {10, 22, 33, 50, 60, 80}.
+*/
+
+#include<bits/stdc++.h>  
+using namespace std; 
+
+int lis( int arr[], int n )  
+{  
+    int lis[n]; 
+   
+    lis[0] = 1;    
+  
+    for (int i = 1; i < n; i++ )  
+    { 
+        lis[i] = 1; 
+        for (int j = 0; j < i; j++ )   
+            if ( arr[i] > arr[j] && lis[i] < lis[j] + 1)  
+                lis[i] = lis[j] + 1;  
+    } 
+  
+    return *max_element(lis, lis+n); 
+}  
+    
+int main()  
+{  
+    int arr[] = { 10, 22, 9, 33, 21, 50, 41, 60 };  
+    int n = sizeof(arr)/sizeof(arr[0]);  
+    printf("Length of lis is %d\n", lis( arr, n ) );  
+    return 0;  
+}