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ashutosh321607Mohamad655
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project_euler_solution_added
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Project Euler/python/problem44.py

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import math
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def pantaNumber(ver):
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return (ver*(3*ver-1))/2
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n = 2500
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panta = []
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for i in range(1,n+1):
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panta.append(pantaNumber(i))
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for i in range(1,n):
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print("value of i =",i)
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for j in range(n-i):
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print("value of (i,j)",(i,j))
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if panta[j+i]+panta[j] in panta:
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if panta[j+i]-panta[j] in panta:
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print("the smallest value D =",panta[j+i]-panta[i])
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quit()
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Project Euler/python/problem45.py

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# n = int(input("Give the value of n "))
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n = 1000000
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prime = [True for i in range(n+1)]
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p = 2
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while (p * p <= n):
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if (prime[p] == True):
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for i in range(p * 2, n+1, p):
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prime[i] = False
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p += 1
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primeNum = []
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for p in range(2, n):
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if prime[p]:
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primeNum.append(p)
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def NumOfPrimeFact(n):
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count=0
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j = 0
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while(n!=1):
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if(n%primeNum[j]==0):
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count+=1
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while(n%primeNum[j]==0):
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n/=primeNum[j]
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j+=1
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return count
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k = int(input("give the value of prime factors: "))
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i = 1
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flag = 0
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while(flag<k):
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if(NumOfPrimeFact(i)==k):
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flag+=1
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else:
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flag = 0
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i+=1
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print("\n\n\t\t*****first number is =",i-k,"*****\n\n")

Project Euler/python/problem668.py

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import math
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import time
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start_time = time.time()
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n = int(input("Give the value of n : "))
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k = math.ceil(math.sqrt(n))
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#genrating prime numbers
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prime = [True for i in range(k+1)]
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p = 2
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while (p * p <= k):
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if (prime[p] == True):
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for i in range(p * 2, k+1, p):
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prime[i] = False
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p += 1
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#storing numbers in a list
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primeNum = []
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for p in range(2, k):
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if prime[p]:
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primeNum.append(p)
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count = 0
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# test Code
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# for i in range(1,n+1):
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# j = 0
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# temp = i
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# while(temp!=1):
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# if(primeNum[j]>=math.sqrt(i)):
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# break
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# if(temp%primeNum[j]==0):
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# temp//=primeNum[j]
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# else:
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# j+=1
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# if(j==len(primeNum)):
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# break
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# if(temp==1):
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# count+=1
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# print(i) # printing value of smooth sqrt numbers
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#Adding 1 because of the number 1 is a smooth sqrt number
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# print("\n\t**Value of smooth square root number below",n,"=",count+1,"**")
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#Optimised code
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x = 0
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for i in range(1,n+1):
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if(primeNum[x]<math.sqrt(i)):
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x+=1
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j = x
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while(j<k-1):
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if(primeNum[j]<=i):
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if(i%primeNum[j]==0):
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count-=1
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print("in")
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break
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else:
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break
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j+=1
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count+=1
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print("out")
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print("\n\t**Value of smooth square root number below",n,"=",count,"**")
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print("--- %s seconds ---" % (time.time() - start_time))

Project Euler/python/problem686.py

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a = int(input())
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n = 2
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myvalue = 0
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i = 1
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while(True):
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i+=1
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n*=2
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n = int(str(n)[:15])
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if(str(n)[:3]=='123'):
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myvalue+=1
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if(myvalue==a):
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break
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print(i)
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