No need to declare Type as inferedType when it is already defined

In the case where there is no init_expression for a variable declaration
and the type was defined on the name we dont need to then assign
that the variable was infered.

Author: philberty

gcc/rust/analysis/rust-type-resolution.cc

@@ -1048,13 +1048,6 @@ TypeResolution::visit (AST::LetStmt &stmt)
 	  return;
 	}
     }
-  else if (stmt.has_type () && !stmt.has_init_expr ())
-    {
-      inferedType = stmt.type.get ();
-    }
-
-  // TODO check we know what the type is in the scope requires the builtins to
-  // be defined at the constructor
 
   // ensure the decl has the type set for compilation later on
   if (!stmt.has_type ())