Skip to content

yet another count_all() bug #128

@djfd

Description

@djfd

Hi,

having the situation of selecting users having 'admin' role and any of some predefined roles set one can use, for example, next sequence

$admins = ORM::factory('Role')->where('name', '=', 'admin')->find()->customers;
// $rids is an array of predefined roles IDs
$admins
    ->distinct(TRUE)
    ->join('customer_role', 'roles_list')->on('roles_list.customer_id', '=', 'user.id')
    ->where('roles_list.role_id', 'in', $rids);

this produces absolutely perfectly valid SQL:

SELECT DISTINCT `user`.*
FROM `customer` AS `user`
JOIN `customer_role` ON (`customer_role`.`customer_id` = `user`.`id`)
JOIN `customer_role` AS `roles_list` ON (`roles_list`.`customer_id` = `user`.`id`)
WHERE `customer_role`.`role_id` = '2' AND `roles_list`.`role_id` IN (2, 9, 1, 8)

However, if we try to count such admins using $admins->count_all() this is rendered to wrong sQL like this:

SELECT DISTINCT COUNT(`user`.`id`) AS `records_found`
FROM `customer` AS `user`
JOIN `customer_role` ON (`customer_role`.`customer_id` = `user`.`id`)
JOIN `customer_role` AS `roles_list` ON (`roles_list`.`customer_id` = `user`.`id`)
WHERE `customer_role`.`role_id` = '2' AND `roles_list`.`role_id` IN (2, 9, 1, 8)

Which in turn gives wrong count. It easy to see that we need to have

SELECT COUNT(DISTINCT user.id)
instead of
SELECT DISTINCT COUNT(user.id)

see https://github.com/kohana/orm/blob/3.3/master/classes/Kohana/ORM.php#L1621
particularly starting from line 1644 (https://github.com/kohana/orm/blob/3.3/master/classes/Kohana/ORM.php#L1644)

Thanks

Metadata

Metadata

Assignees

No one assigned

    Labels

    No labels
    No labels

    Type

    No type

    Projects

    No projects

    Milestone

    No milestone

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions