incombustible

[hahaha666123-arch]

Hello friends and experts! I am simulating the process of burning an incendiary in a cardboard box at a specified hrr and then igniting the box, perhaps because the box is completely closed so the incendiary does not burn at the specified hrr, I would like to ask you all what is wrong with this? How should I modify it to achieve the desired result.
Here is my code：
&TIME T_END=120/
&MISC SIMULATION_MODE='LES'/
&MESH IJK=60,20,60, XB=-0.3,0.3,-0.1,0.1,0.0,0.6 /
&SLCF QUANTITY='TEMPERATURE',CELL_CENTERED=T,PBY=0/
&SLCF QUANTITY='VELOCITY',CELL_CENTERED=T,PBY=0/
&SPEC ID='MYFUEL1'
FORMULA= C6.3H7.1O2.1N
/
&SPEC ID='MYFUEL2'
FORMULA= C6H10O5
/
&SPEC ID='OXYGEN'/
&REAC FUEL= 'MYFUEL1'
CO_YIELD=0.003,
SOOT_YIELD=1.3E-6 RADIATIVE_FRACTION=0.32/
&REAC ID='PAPER_REAC',
FUEL='MYFUEL2',
SOOT_YIELD=0.02,
CO_YIELD=0.02,
HEAT_OF_COMBUSTION=15000 RADIATIVE_FRACTION=0.32/
&MATL ID='b',
SPECIFIC_HEAT=1.22,
CONDUCTIVITY=22.6,
DENSITY=2175,
/
&MATL ID='CONCRETE',
SPECIFIC_HEAT=1.04,
CONDUCTIVITY=1.8,
DENSITY=2280.0/
&MATL ID='STEEL',
SPECIFIC_HEAT=0.46,
CONDUCTIVITY=45.8,
DENSITY=7850.0,
EMISSIVITY=0.95/
&MATL ID='PLANE',
DENSITY=700,
CONDUCTIVITY=0.08,
SPECIFIC_HEAT=1.3,
EMISSIVITY=0.9,
/
&SURF ID='Beton',
RGB=212,172,174,
MATL_ID(1,1)='CONCRETE',
MATL_MASS_FRACTION(1,1)=1.0,
THICKNESS(1)=0.2/
&SURF ID='STEEL',
MATL_ID(1,1)='STEEL',
MATL_MASS_FRACTION(1,1)=1.0,
THICKNESS(1)=0.01,
/
&SURF ID='b',
COLOR='RED',
MATL_ID(1,1)='b',
MATL_MASS_FRACTION(1,1)=1.0,
THICKNESS(1)=0.01,
STRETCH_FACTOR=1.0,
HRRPUA=100
RAMP_Q='b_RAMP_Q'
SPEC_ID='MYFUEL1'/
&SURF ID='PLANE',
MATL_ID(1,1)='PLANE'
THICKNESS(1)=0.01
HRRPUA=350,
SPEC_ID='MYFUEL2'
RAMP_Q='PLANE_RAMP_Q'
IGNITION_TEMPERATURE=260
BURN_AWAY = .TRUE./
&RAMP ID='b_RAMP_Q', T=0, F=0.0/
&RAMP ID='b_RAMP_Q', T=11, F=0.0/
&RAMP ID='b_RAMP_Q', T=22, F=0.0/
&RAMP ID='b_RAMP_Q', T=30, F=0.0081/
&RAMP ID='b_RAMP_Q', T=31, F=0.078/
&RAMP ID='b_RAMP_Q', T=32, F=0.19/
&RAMP ID='b_RAMP_Q', T=33, F=0.33/
&RAMP ID='b_RAMP_Q', T=34, F=0.45/
&RAMP ID='b_RAMP_Q', T=37, F=0.6/
&RAMP ID='b_RAMP_Q', T=38, F=0.81/
&RAMP ID='b_RAMP_Q', T=42, F=0.89/
&RAMP ID='b_RAMP_Q', T=46, F=0.94/
&RAMP ID='b_RAMP_Q', T=50, F=1/
&RAMP ID='b_RAMP_Q', T=52, F=0.87/
&RAMP ID='b_RAMP_Q', T=56, F=0.62/
&RAMP ID='b_RAMP_Q', T=59, F=0.42/
&RAMP ID='by_RAMP_Q', T=61, F=0.26/
&RAMP ID='b_RAMP_Q', T=65, F=0.11/
&RAMP ID='b_RAMP_Q', T=77, F=0/
&RAMP ID='b_RAMP_Q', T=100, F=0/

&RAMP ID='PLANE_RAMP_Q', T=0.0, F=0.0/

&RAMP ID='PLANE_RAMP_Q', T= 15, F=0.1/

&RAMP ID='PLANE_RAMP_Q', T= 50, F=1/

&RAMP ID='PLANE_RAMP_Q', T= 75, F=0.3/

&RAMP ID='PLANE_RAMP_Q', T= 100, F=0/

&OBST ID= 'B'
XB= -0.268 0.268 -0.051 0.051 0 0.009
SURF_IDS='b','STEEL','STEEL'/
&OBST ID= 'Carton'
XB= -0.3 0.3 -0.075 0.075 0 0.3
SURF_ID='PLANE'/
&VENT MB='XMIN', SURF_ID='OPEN' /
&VENT MB='XMAX', SURF_ID='OPEN' /
&VENT MB='YMIN', SURF_ID='OPEN' /
&VENT MB='YMAX', SURF_ID='OPEN' /
&VENT MB='ZMAX', SURF_ID='OPEN' /
&VENT ID='Vent', SURF_ID='Beton',
XB=-0.3,0.3,-0.1,0.1,0.0,0/
&DEVC ID= 'T-1'
QUANTITY = 'TEMPERATURE'
XYZ= 0 0 0.11/
&DEVC ID= 'T-2'
QUANTITY = 'TEMPERATURE'
XYZ= 0 0 0.31/
&DEVC ID= 'T-3'
QUANTITY = 'TEMPERATURE'
XYZ= 0 0 0.51/
&DEVC ID= 'T-4'
QUANTITY = 'TEMPERATURE'
XYZ= 0 0 0.6/

&DEVC ID='s000', XB=0.1,0.3,0,0,0.1,0.1, ORIENTATION=0,-1,0, POINTS=10,
QUANTITY='RADIATIVE HEAT FLUX GAS', X_ID='x distance' /
&DEVC ID='s050', XB=0.1,0.3,0,0,0.2,0.2, ORIENTATION=0,-1,0, POINTS=10,
QUANTITY='RADIATIVE HEAT FLUX GAS', HIDE_COORDINATES=.TRUE. /
&DEVC ID='s100', XB=0.1,0.3,0,0,0.3,0.3, ORIENTATION=0,-1,0, POINTS=10,
QUANTITY='RADIATIVE HEAT FLUX GAS', HIDE_COORDINATES=.TRUE. /
&DEVC ID='s150', XB=0.1,0.3,0,0,0.5,0.5, ORIENTATION=0,-1,0, POINTS=10,
QUANTITY='RADIATIVE HEAT FLUX GAS', HIDE_COORDINATES=.TRUE. /
&DUMP DT_DEVC=3/
&TAIL /

[drjfloyd]

This is a completely solid block of material. This is not a hollow box. There is no void space inside of this.

&OBST ID= 'Carton'
XB= -0.3 0.3 -0.075 0.075 0 0.3
SURF_ID='PLANE'/

This OBST is entirely inside the solid block defined above. There is no wall cell as the OBST is completely inside of another solid.

&OBST ID= 'B'
XB= -0.268 0.268 -0.051 0.051 0 0.009
SURF_IDS='b','STEEL','STEEL'/

[hahaha666123-arch]

Thank you for your reply, does FDS have a code that can create hollow objects that contain oxygen inside?

[hahaha666123-arch]

Or can I create six planes instead of the individual surfaces of the carton to set the thickness, which together make up the carton?

[Vojta-Salek]

All answers can be found in the User's Guide. Creating objects (possibly with holes) is described in Chapter 7 (Model geometry). Take a look at that and if there is still something unclear, someone can surely help you with a specific problem.