Check if page is panelized: $no_panels ?

[maxplus]

Hi,

In Kalatheme's template.php we have:

 // If panels arent being used at all.
  $variables['no_panels'] = !(module_exists('page_manager') && page_manager_get_current_page());

This is useful in your own page.tpl.php so can add a container class if you have a page that is not based on panels:
<div class="column <?php $no_panels ? print 'container' : ''; ?>">

My problem is that this does not work for a panelized page.
In my use case I would also like to detect that the current page is panelized and in that case don't add the container class.

Does anybody know how to detect that a page is panelized in the same way we do this for a page manager panels page?

[maxplus]

Hi,

I have solved my issue by doing this:

1. I have one landing page content type that I used with panelizer; it is called "landingspagina"
2. I wrote a function in my template.php:

function MYTHEME_preprocess_page(&$variables) {
  if (!((module_exists('page_manager') && page_manager_get_current_page())) && !$variables['node']->type == 'landingspagina') {
    $variables['container'] = 'container';  }
}

1. in my page.tpl.php I have changed

<div id="content">
        <div class="column <?php $no_panels ? print 'container' : ''; ?>">

to this:

 <div id="content">
        <div class="column <?php print $container; ?>">

[UTANdev]

Like @maxplus, I'm getting double .container elements on panelized pages. Since I'm using Panelizer all over the place, I can't implement a content-type based solution as above.

Isn't there a way to improve the $no_panels test (commit 9f09493) to account for panelized pages?