Question regarding result interpretation of RatcliffObershelpSimilarity #2
Description
Just for my clarification: A comparison of two identical strings should always yield a 1.0 as result, correct?
string s1 = "hello world";
string s2 = "hello world";
double x = s1.RatcliffObershelpSimilarity(s2);
-> x = 0.7272727272
Also, I was trying to get the same numbers like on this page for reference checking: https://itnext.io/string-similarity-the-basic-know-your-algorithms-guide-3de3d7346227
But already the first example differs:
string1, string2 = "i am going home", "gone home"
textdistance.ratcliff_obershelp(string1, string2)
0.66
Your extension: 0.58333333
string1, string2 = "test", "text"
textdistance.ratcliff_obershelp(string1, string2)
0.75
Your extension: 0.5
Am I using the extension wrong or is there a problem with the implementation?