Empty EOL in for /F statement

[andry81]

Started from: #3

FOR /F "tokens=* delims=#"EOL^= %%L in (somefile) do echo ...%%L

[jeb-de]

I don't see the reason for delims=#, it should be just delims= to avoid stripping of leading # characters.

FOR /F "tokens=* delims=#"EOL^= %%L in ("####my test") do echo ...%%L

[andry81]

Yes, it can be removed. I've just copied it as is, because it was in the original post: #3 (comment)