|
| 1 | +""" |
| 2 | +Problem Overview: |
| 3 | +
|
| 4 | +Is Palindrome - Easy - Spotify |
| 5 | +
|
| 6 | +Given a string s, return true if it is a palindrome, otherwise return false. |
| 7 | +
|
| 8 | +A palindrome is a string that reads the same forward and backward. |
| 9 | +It is also case-insensitive and ignores all non-alphanumeric characters. |
| 10 | +
|
| 11 | +Example 1: |
| 12 | +
|
| 13 | +Input: s = "Was it a car or a cat I saw?" |
| 14 | +
|
| 15 | +Output: true |
| 16 | +Explanation: After considering only alphanumerical characters |
| 17 | +we have "wasitacaroracatisaw", which is a palindrome. |
| 18 | +
|
| 19 | +Example 2: |
| 20 | +
|
| 21 | +Input: s = "tab a cat" |
| 22 | +
|
| 23 | +Output: false |
| 24 | +Explanation: "tabacat" is not a palindrome. |
| 25 | +
|
| 26 | +Constraints: |
| 27 | +
|
| 28 | +1 <= s.length <= 1000 |
| 29 | +s is made up of only printable ASCII characters. |
| 30 | +
|
| 31 | +""" |
| 32 | + |
| 33 | + |
| 34 | +class Solution: |
| 35 | + def is_palindrome(self, s: str) -> bool: |
| 36 | + """ |
| 37 | + This method checks whether the input string `s` is a palindrome or not. |
| 38 | + It ignores non-alphanumeric characters and is case-insensitive. |
| 39 | +
|
| 40 | + Parameters: |
| 41 | + s (str): The input string to check. |
| 42 | +
|
| 43 | + Returns: |
| 44 | + bool: True if the string is a palindrome, False otherwise. |
| 45 | +
|
| 46 | + >>> Solution().is_palindrome("Was it a car or a cat I saw?") |
| 47 | + True |
| 48 | + >>> Solution().is_palindrome("tab a cat") |
| 49 | + False |
| 50 | + >>> Solution().is_palindrome("") |
| 51 | + True |
| 52 | + >>> Solution().is_palindrome("A") |
| 53 | + True |
| 54 | + """ |
| 55 | + |
| 56 | + """ |
| 57 | + Initialize two pointers, left (l) at the start, and right (r) at |
| 58 | + the end of the string. |
| 59 | + """ |
| 60 | + left, right = 0, len(s) - 1 |
| 61 | + |
| 62 | + while left < right: |
| 63 | + # Skip non-alphanumeric characters from the left pointer. |
| 64 | + while left < right and not self.is_alpha_numeric(s[left]): |
| 65 | + left += 1 |
| 66 | + # Skip non-alphanumeric characters from the right pointer. |
| 67 | + while left < right and not self.is_alpha_numeric(s[right]): |
| 68 | + right -= 1 |
| 69 | + |
| 70 | + # Compare characters at both pointers in a case-insensitive way. |
| 71 | + if s[left].lower() != s[right].lower(): |
| 72 | + return False |
| 73 | + |
| 74 | + # Move both pointers towards the center. |
| 75 | + left, right = left + 1, right - 1 |
| 76 | + |
| 77 | + # If all characters match, it is a palindrome. |
| 78 | + return True |
| 79 | + |
| 80 | + def is_alpha_numeric(self, c: str) -> bool: |
| 81 | + """ |
| 82 | + Helper function to check if a character is alphanumeric (A-Z, a-z, 0-9). |
| 83 | +
|
| 84 | + Parameters: |
| 85 | + c (str): The character to check. |
| 86 | +
|
| 87 | + Returns: |
| 88 | + bool: True if the character is alphanumeric, False otherwise. |
| 89 | + """ |
| 90 | + return ( |
| 91 | + ord("A") <= ord(c) <= ord("Z") |
| 92 | + or ord("a") <= ord(c) <= ord("z") |
| 93 | + or ord("0") <= ord(c) <= ord("9") |
| 94 | + ) |
| 95 | + |
| 96 | + |
| 97 | +if __name__ == "__main__": |
| 98 | + import doctest |
| 99 | + |
| 100 | + doctest.testmod() |
0 commit comments