From cd4efc51cd142d5029183b66bebed0150d15bd70 Mon Sep 17 00:00:00 2001 From: Fabiana Campanari Date: Sat, 1 Jun 2024 23:53:54 -0300 Subject: [PATCH] Update README.md Signed-off-by: Fabiana Campanari --- README.md | 7 ++++++- 1 file changed, 6 insertions(+), 1 deletion(-) diff --git a/README.md b/README.md index d601b05..f6ebccb 100644 --- a/README.md +++ b/README.md @@ -199,15 +199,20 @@ $$\lim_{x \to -\infty} \frac{1}{x^2}$$ Similar to the previous case, as x approaches negative infinity, the denominator ($x^2$) grows infinitely large (but remains positive), and the numerator remains constant at 1. - +
The fraction becomes increasingly small, approaching zero. +
Solution: $$\lim_{x \to -\infty} \frac{1}{x^2} = 0$$ +$ + + +