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@dlfivefifty The lowering Zernike(0,1) \ Weighted(Zernike(0,1))
is a factor of 2 off. This also seems to be confirmed in the tests..?
@test 2w*Zernike(1)[xy,Block.(1:5)]' ≈ Zernike(1)[xy,Block.(1:7)]'*L[Block.(1:7),Block.(1:5)] |
Is there a reason for this?
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