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I think we can do any star like geometry as long as we can do the boundary: consider it as
p(x/z,y/z) = 1
for z = 0..1
(disk being classic example). Then we can construct OPs in 3-variables x,y,z
from boundary OPs in 2 variables Y_{m,k}(x,y)
as
Q_{m,k,i}(x,y,z) = P_k^(0,2m+1)(2z-1) * z^m * Y_{m,i}(x/z,y/z)
Claims to be double checked:
- This spans all polynomials in
x,y,z
mod the constraintp(x/z,y/z) =1
, which is in fact a polynomial constraint: ifp
is degreed
just multiply through byz^d
. - This basis is orthogonal w.r.t.
\int_0^1 \int_{z B} f(x,y,z) g(x,y,z) dx dy dz
To get back to OPs in 2-variables we would then construct the connection matrix. Since Q_{m,k,i}
spans all polynomials, it contains 2-variable polynomials as a sub space. We can compute this connection matrix by Lanczos (that is, multiply by x
and y
).
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