|
| 1 | +--- |
| 2 | +title: 手写算法题合集 |
| 3 | +tags: front interview |
| 4 | +theme: solarized-dark |
| 5 | +--- |
| 6 | + |
| 7 | +# LeetCode 经典算法题目整理 |
| 8 | + |
| 9 | +## 1. 两数之和 |
| 10 | + |
| 11 | +```javascript |
| 12 | +function twoSum(nums, target) { |
| 13 | + if (nums.length <= 1) return []; |
| 14 | + const map = new Map(); |
| 15 | + for (let i = 0; i < nums.length; i++) { |
| 16 | + if (map.has(target - nums[i])) { |
| 17 | + return [map.get(target - nums[i]), i]; |
| 18 | + } else { |
| 19 | + map.set(nums[i], i); |
| 20 | + } |
| 21 | + } |
| 22 | + return []; |
| 23 | +} |
| 24 | +``` |
| 25 | + |
| 26 | +## 2. 最大子序和 |
| 27 | + |
| 28 | +```javascript |
| 29 | +function maxSubArray(nums) { |
| 30 | + let prev = 0; |
| 31 | + let max = nums[0]; |
| 32 | + nums.forEach((value) => { |
| 33 | + prev = Math.max(prev + value, value); |
| 34 | + max = Math.max(prev, max); |
| 35 | + }); |
| 36 | + return max; |
| 37 | +} |
| 38 | +``` |
| 39 | + |
| 40 | +## 3. 反转链表 |
| 41 | + |
| 42 | +```javascript |
| 43 | +function reverseList(head) { |
| 44 | + let prev = null; |
| 45 | + let current = head; |
| 46 | + while (current) { |
| 47 | + const next = current.next; |
| 48 | + current.next = prev; |
| 49 | + prev = current; |
| 50 | + current = next; |
| 51 | + } |
| 52 | + return prev; |
| 53 | +} |
| 54 | +``` |
| 55 | + |
| 56 | +## 4. 比较版本号 |
| 57 | + |
| 58 | +```javascript |
| 59 | +function compareVersion(version1, version2) { |
| 60 | + const arr1 = version1.split("."); |
| 61 | + const arr2 = version2.split("."); |
| 62 | + let maxLength = Math.max(arr1.length, arr2.length); |
| 63 | + for (let i = 0; i < maxLength; i++) { |
| 64 | + if (Number(arr1[i]) > Number(arr2[i])) { |
| 65 | + return 1; |
| 66 | + } |
| 67 | + if (Number(arr1[i]) < Number(arr2[i])) { |
| 68 | + return -1; |
| 69 | + } |
| 70 | + if (i === maxLength - 1) { |
| 71 | + return 0; |
| 72 | + } |
| 73 | + } |
| 74 | +} |
| 75 | +``` |
| 76 | + |
| 77 | +## 5. 合并两个有序数组 |
| 78 | + |
| 79 | +```javascript |
| 80 | +function mergeSortArray(nums1, m, nums2, n) { |
| 81 | + let i = m - 1; |
| 82 | + let j = n - 1; |
| 83 | + let k = m + n - 1; |
| 84 | + while (i >= 0 || j >= 0) { |
| 85 | + if (i < 0) nums1[k--] = nums2[j--]; |
| 86 | + if (j < 0) nums1[k--] = nums1[i--]; |
| 87 | + if (nums1[i] < nums2[j]) nums1[k--] = nums2[j--]; |
| 88 | + else nums1[k--] = nums1[i--]; |
| 89 | + } |
| 90 | +} |
| 91 | +``` |
| 92 | + |
| 93 | +## 6. 无重复字符的最长子串 |
| 94 | + |
| 95 | +```javascript |
| 96 | +function lengthOfLongestSubstring(s) { |
| 97 | + let max = 0; |
| 98 | + let startIndex = 0; |
| 99 | + let map = new Map(); |
| 100 | + |
| 101 | + for (let i = 0; i < s.length; i++) { |
| 102 | + if (map.has(s[i])) { |
| 103 | + startIndex = map.get(s[i]) + 1; |
| 104 | + } |
| 105 | + max = Math.max(i - startIndex + 1, max); |
| 106 | + map.set(s[i], i); |
| 107 | + } |
| 108 | + return max; |
| 109 | +} |
| 110 | +``` |
| 111 | + |
| 112 | +## 7. 有效的括号 |
| 113 | + |
| 114 | +```javascript |
| 115 | +function validParenthesis(s) { |
| 116 | + const map = { |
| 117 | + "}": "{", |
| 118 | + "]": "[", |
| 119 | + ")": "(", |
| 120 | + }; |
| 121 | + const stack = []; |
| 122 | + |
| 123 | + for (let i = 0; i < s.length; i++) { |
| 124 | + if (stack.length && stack[stack.length - 1] === map[s[i]]) { |
| 125 | + stack.pop(); |
| 126 | + } else { |
| 127 | + stack.push(s[i]); |
| 128 | + } |
| 129 | + } |
| 130 | + return !stack.length; |
| 131 | +} |
| 132 | +``` |
| 133 | + |
| 134 | +## 8. LRU 缓存机制 |
| 135 | + |
| 136 | +```javascript |
| 137 | +class LRUCache { |
| 138 | + constructor(capacity) { |
| 139 | + this.capacity = capacity; // 缓存的最大容量 |
| 140 | + this.cache = new Map(); // 使用 Map 存储缓存数据 |
| 141 | + } |
| 142 | + |
| 143 | + // 获取缓存数据 |
| 144 | + get(key) { |
| 145 | + if (!this.cache.has(key)) { |
| 146 | + return -1; // 如果缓存中没有该数据,则返回 -1 |
| 147 | + } |
| 148 | + // 如果数据存在,先删除再重新插入(表示该数据被访问过,更新为最近使用) |
| 149 | + const value = this.cache.get(key); |
| 150 | + this.cache.delete(key); |
| 151 | + this.cache.set(key, value); |
| 152 | + return value; |
| 153 | + } |
| 154 | + |
| 155 | + // 设置缓存数据 |
| 156 | + put(key, value) { |
| 157 | + // 如果缓存已满,删除最旧的数据 |
| 158 | + if (this.cache.size >= this.capacity) { |
| 159 | + // Map 的 keys() 返回插入顺序,删除第一个元素 |
| 160 | + this.cache.delete(this.cache.keys().next().value); |
| 161 | + } |
| 162 | + // 如果已经存在这个 key,删除旧值并插入新值 |
| 163 | + if (this.cache.has(key)) { |
| 164 | + this.cache.delete(key); |
| 165 | + } |
| 166 | + // 插入新数据到缓存 |
| 167 | + this.cache.set(key, value); |
| 168 | + } |
| 169 | +} |
| 170 | + |
| 171 | +// 测试代码 |
| 172 | +const lru = new LRUCache(2); |
| 173 | +lru.put(1, 1); // 缓存 {1=1} |
| 174 | +lru.put(2, 2); // 缓存 {1=1, 2=2} |
| 175 | +console.log(lru.get(1)); // 返回 1,缓存 {2=2, 1=1} |
| 176 | +lru.put(3, 3); // 缓存已满,删除最久未使用的 2,缓存 {1=1, 3=3} |
| 177 | +console.log(lru.get(1)); // 返回 -1 (未找到) |
| 178 | +lru.put(4, 4); // 缓存 {3=3, 4=4} |
| 179 | +console.log(lru.get(2)); // 返回 -1 (未找到) |
| 180 | +console.log(lru.get(3)); // 返回 3 |
| 181 | +console.log(lru.get(4)); // 返回 4 |
| 182 | +``` |
| 183 | + |
| 184 | +## 9. 买卖股票的最佳时机 |
| 185 | + |
| 186 | +```javascript |
| 187 | +function maxProfit(prices) { |
| 188 | + let minPrice = prices[0]; |
| 189 | + let maxProfit = 0; |
| 190 | + for (let i = 1; i < prices.length; i++) { |
| 191 | + minPrice = Math.min(prices[i], minPrice); |
| 192 | + maxProfit = Math.max(maxProfit, prices[i] - minPrice); |
| 193 | + } |
| 194 | + return maxProfit; |
| 195 | +} |
| 196 | +``` |
| 197 | + |
| 198 | +## 10. 最长回文子串 |
| 199 | + |
| 200 | +```javascript |
| 201 | +function longestPalindrome(s) { |
| 202 | + let l = 0; |
| 203 | + let r = 0; |
| 204 | + |
| 205 | + for (let i = 0; i < s.length; i++) { |
| 206 | + helper(i, i); |
| 207 | + helper(i, i + 1); |
| 208 | + } |
| 209 | + |
| 210 | + function helper(m, n) { |
| 211 | + while (m >= 0 && n < s.length && s[m] == s[n]) { |
| 212 | + m--; |
| 213 | + n++; |
| 214 | + } |
| 215 | + if (n - m > r - l) { |
| 216 | + r = n; |
| 217 | + l = m; |
| 218 | + } |
| 219 | + } |
| 220 | + return s.slice(l + 1, r); |
| 221 | +} |
| 222 | +``` |
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