From f96cbef8f75df70ef057689d5bf259589fd78e73 Mon Sep 17 00:00:00 2001
From: gautamrishabh <73752239+gautamrishabh@users.noreply.github.com>
Date: Sun, 31 Oct 2021 18:07:33 +0530
Subject: [PATCH] Hacktober Fest 2021

Pull Request
---
 Gold Mine | 61 +++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 61 insertions(+)
 create mode 100644 Gold Mine

diff --git a/Gold Mine b/Gold Mine
new file mode 100644
index 00000000..26c58cc9
--- /dev/null
+++ b/Gold Mine	
@@ -0,0 +1,61 @@
+// C++ program to solve Gold Mine problem
+#include<bits/stdc++.h>
+using namespace std;
+
+const int MAX = 100;
+
+// Returns maximum amount of gold that can be collected
+// when journey started from first column and moves
+// allowed are right, right-up and right-down
+int getMaxGold(int gold[][MAX], int m, int n)
+{
+	// Create a table for storing intermediate results
+	// and initialize all cells to 0. The first row of
+	// goldMineTable gives the maximum gold that the miner
+	// can collect when starts that row
+	int goldTable[m][n];
+	memset(goldTable, 0, sizeof(goldTable));
+
+	for (int col=n-1; col>=0; col--)
+	{
+		for (int row=0; row<m; row++)
+		{
+			// Gold collected on going to the cell on the right(->)
+			int right = (col==n-1)? 0: goldTable[row][col+1];
+
+			// Gold collected on going to the cell to right up (/)
+			int right_up = (row==0 || col==n-1)? 0:
+							goldTable[row-1][col+1];
+
+			// Gold collected on going to the cell to right down (\)
+			int right_down = (row==m-1 || col==n-1)? 0:
+							goldTable[row+1][col+1];
+
+			// Max gold collected from taking either of the
+			// above 3 paths
+			goldTable[row][col] = gold[row][col] +
+							max(right, max(right_up, right_down));
+													
+		}
+	}
+
+	// The max amount of gold collected will be the max
+	// value in first column of all rows
+	int res = goldTable[0][0];
+	for (int i=1; i<m; i++)
+		res = max(res, goldTable[i][0]);
+	return res;
+}
+
+// Driver Code
+int main()
+{
+	int gold[MAX][MAX]= { {1, 3, 1, 5},
+		{2, 2, 4, 1},
+		{5, 0, 2, 3},
+		{0, 6, 1, 2}
+	};
+	int m = 4, n = 4;
+	cout << getMaxGold(gold, m, n);
+	return 0;
+}